Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 1 )

Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 12 )

. 2 12 10 3 1 8547 11 9...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 11 )

. 264359 1 7 10 ...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 10 )

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 9 )

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 7 )

. DNA is transcribed into RNA, the sequence of the resulting RNA transcript will be ____. A. 5’-TCGGCAC-3’ B. 5’-CUAAUGA-3’ C. 5’-TGTAATC-3’ D. 5’-UGUAAUC-3’ E. 5’-GAUUACA’3’ 41. The endomembrane. hormone ( 12 5I-hormone) for five minutes. A second sample of membranes was prepared and treated similarly with the addition of 12 5I-hormone but this sample also contained a 10 00-fold excess. competitive inhibitor (I)? Page 3 of 8 17 . Which of the following statements is FALSE about a chemical reaction whose equilibrium constant (Keq ) is greater than 10 4 at 37°C? A. The...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 6 )

. Stdev = 12 .3, Median score = 78, Range 3 4-9 8. A+ = 9 8 -1 00, A =9 2-9 7, A- = 9 0- 92, B+ = 8 8-8 9, B = 84 - 87, B- = 8 0-8 3, C+ = 7 6-7 9, C = 72 - 75, C- = 62 - 71, D+ = 5 8-6 1, D= 5 4- 57, D- = 51 - 53.. EXAM 1 ANSWER KEY Fall 2 011 ANSWER KEY EXAM 1, Fall 2 011 The exam was worth 10 0 points. All questions (except 51 for version B) were worth 2 points. The columns. a b a b a b a b 1 D C 6 C B 11 A D 16 B A 21 A D 26 B B 31 E E 36 C D 41 A E 46 C C 2 B C 7 A A 12 E E 17 C E 22 D B 27 C C 32...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 5 )

. properly based DNA? A) 5’-CGAT-3’ with 5’-GGTA-3’ B) 5’-TAAT-3’ with 5’-ATTG-3’ C) 5’-GGCC-3’ with 5’-AATT-3’ D) 5’-ATCG-3’ with 5’-CGAT-3’ E) 5’-ATAT-3’ with 5’-TATA-3’ 34. Allosteric. substrate level phosphorylation in your answer. A) 3 (NADH + H+ ), 1 FADH2, 2 CO2, eventually 9 ATP B) 3 (NADPH + H+ ), 1 FADH2, 3 CO2, eventually 10 ATP C) 3 (NADH + H+ ), 1 FADH2,. H+ ), 1 FADH2, 3 CO2, eventually 11 .5 ATP D) 4 (NADH + H+ ), 1 FADH2, 3 CO2, eventually 12 .5 ATP E) 4 (NADH + H+ ), 1 FADH2, 3 CO2, eventually 13 .5 ATP 27. Hydrogen bonds between...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 13 )

. with the 1 FADH2 from Krebs. Each of the (NADH + H+ ) will yield 2.5 ATP. 4 X 2.5 = 10 . The FADH2 will yield 1. 5 ATP (less than (NADH + H+ ). There is 1 ATP from SLP yielding a total of 12 .5. EXAM 1 ANSWER KEY Version A/B Fall 2 012 26/30 We are starting with pyruvate so we must yield 3 CO2. We need to be sure to include the (NADH + H+ ) from pyruvate oxidation, the 3 (NADH + H+ ). increase the rate of the electron transport chain. 33/35 DNA is double stranded, anti-parallel and must follow base pairing rules (A with T, C with G). 34/3 4) Allosteric effectors bind at sites...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 4 )

. ''.,n-\ 'Jn, \-] drn!r3*Page 4 of 8r(B)'f'r-*2. Ial 10 .5+GII () Time2tE- o.sltu1 I-t-I+I t 'tim.: 41. For the enzyme-catalyzed reaction S 1) . ) Electron transport chain ) Water'p-NnOeH ) Electron transport chain ) Calvin cycle ) Water ) NADP* ) SugarsE Calvin cycle ) Electron transport chain ) Water ) NADPH ) Sugars33.. Water ) Sugars ) Glycolysis ) Calvin cycle ) Electron transport chainfE) Water ) Electron transport chain ) NADPH ) Calvin cycle ) Sugars-G _sugars > NADPH ) Calvin cycle ) Electron...

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Đề kiểm tra môn sinh học quốc tế - Ngôn ngữ tiếng anh ( Đề 3 )

. cytosol D. their proteins are imported by both co- and post-translational pathways E. their proteins are exported to the cytosol 22. (1 pt) Peripheral proteins A. are imbedded in the hydrophobic. > O2 43. Substrate-level phosphorylation and oxidative phosphorylation differ because A. only substrate-level phosphorylation occurs in an organelle B. only substrate-level phosphorylation. BIOLOGY 1A MIDTERM # 1 February 17 th, 2 012 NAME SECTION # DISCUSSION GSI 1. Sit every other seat and sit by section number. Place all...

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